Asked by Anonymous
The function g(x) is a transformed image of the graph of f(x)=2^x. Write the equation of the transformed function g(x) in the form g(x)= b^x-h+k.
f(x)
(0,1)
(2,4)
g(x)
(-1,2)
(-3,-1)
f(x)
(0,1)
(2,4)
g(x)
(-1,2)
(-3,-1)
Answers
Answered by
Steve
2^(-1-h)+k = 2
2^(-3-h)+k = -1
solve for h and k
Of course many other values for b could have been chosen, but since only two data points were given, something had to be assumed.
2^(-3-h)+k = -1
solve for h and k
Of course many other values for b could have been chosen, but since only two data points were given, something had to be assumed.
Answered by
Steve
just in case you are having trouble solving exponential equations,
eliminate k and you have
2 - 2^(-1-h) = -1 - 2^(-3-h)
3 = 2^(-1-h) - 2^(-3-h)
3 = 2^-h/2 - 2^-h/8
3 = 2^-h (1/2 - 1/8)
3 = 2^-h * 3/8
8 = 2^-h
h = -3
Then k = -2, and
g(x) = 2^(x+3)-2
See the graph at
http://www.wolframalpha.com/input/?i=2%5E(x%2B3)-2+for+-4+%3C+x+%3C+0
eliminate k and you have
2 - 2^(-1-h) = -1 - 2^(-3-h)
3 = 2^(-1-h) - 2^(-3-h)
3 = 2^-h/2 - 2^-h/8
3 = 2^-h (1/2 - 1/8)
3 = 2^-h * 3/8
8 = 2^-h
h = -3
Then k = -2, and
g(x) = 2^(x+3)-2
See the graph at
http://www.wolframalpha.com/input/?i=2%5E(x%2B3)-2+for+-4+%3C+x+%3C+0
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