The function f is given by f(x)=3x^2+1. What is the average value of f over the closed interval [1,3]?

The answer I get is 12, but the book says it's 14. I don't understand why.

2 answers

I also get 12.
wait. 12 is the average slope:

(f(3)-f(1))/(2-1)

The average value is the integral

∫[1,3] f(x) dx
----------------- = 14
    2
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