The function f is given by f(x)=3x^2+1. What is the average value of f over the closed interval [1,3]?
The answer I get is 12, but the book says it's 14. I don't understand why.
2 answers
I also get 12.
wait. 12 is the average slope:
(f(3)-f(1))/(2-1)
The average value is the integral
∫[1,3] f(x) dx
----------------- = 14
2
(f(3)-f(1))/(2-1)
The average value is the integral
∫[1,3] f(x) dx
----------------- = 14
2
2 answers