The function f is defined by f(x)=2x^2-6x+5

Find the set of values of p for which the equation f(x)=p has no real roots.

Thanks in advance!

3 answers

The given quadratic equation has no real roots when the determinant is (strictly) negative.
This happens when
b^2-4*a*c-p<0, or
(-6)^2-4(2)(5)-p<0
=>
p>36-40=-4
So the condition for f(x)=p has no real roots is when p>-4.

lund

didnt distribute to p

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