Question

The function ax(t) describes the acceleration of a particle moving along the x-axis. At time t=0, the particle is located at the position x0 and the velocity of the particle is zero.

ax(t)=a0e−bt

The numerical values of all parameters are listed below:

x0=980 m
a0=500 ms2
b=600 s−1
t1=120 s
t2=110 s

Calculate the change in velocity vx between time t=0 and t=t1.
vx= 8.33×10-1 m/s

Calculate the change in position x between time t=0 and t=t1.
x=??

Calculate the average velocity vxave between time t=0 and t=t2.
vxave=???

Calculate the average acceleration of the particle axave between time t=0 and t=t2.
axave= ???