The frist term of an A.P is equal to twice the common difference d mean:
a1 = 2 d
nth term of the A.P:
an = a1 + ( n - 1 ) d
a5 = a1 + ( 5 - 1 ) d
a5 = a1 + 4 d
Since a1 = 2 d
a5 = a1 + 4 d = 2 d + 4 d = 6 d
a5 = 6 d
THE FRIST TERM OF AN A.P IS EQUAL TO TWICE THE COMMON DIFFERENCE D FIND IN TERM OF D THE 5TH TERM OF THE A.P
5 answers
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2 answers