The free-fall acceleration on Mars is 3.7 m/s2.

Question

(b)What length of pendulum would have a 0.9 s period on Mars?

Answer 1

T^2 = 4*(pi)^2(L/g) = 90.9)^2
4*(3.14)^2(L/g) = 0.81
39.48(L/g) = 0.81
L/g = 0.02052
L = 0.02052*3.7 = 0.076 m.

Answer 2

The freefall acceleration is 9.8m/s square.what period has pendulum of 2.5m length?