If a student measures the length of the pendulum to be 0.510m in a simple pendulum experiment and determines that the period of the pendulum is 1.44s. Determine the experimental value of the acceleration due to gravity

Answer 1

We can use the equation for the period of a simple pendulum:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

Rearranging this equation to solve for g, we get:

g = (4π^2L) / T^2

Substituting the given values, we get:

g = (4π^2 x 0.510m) / (1.44s)^2

Simplifying this expression, we get:

g ≈ 9.69 m/s^2

Therefore, the experimental value of the acceleration due to gravity is approximately 9.69 m/s^2, based on the measurements of the length and period of the pendulum.