The fourth term of an A.P is equal to 3 times the first term and the seventh term exceeds twice the third term by 2. The first term and the common difference are:

Answer 1

a+3d = 3a
a+6d = 2(a+2d)+2

now just crank it out.

Answer 2

The first term of ap exceed twice the second term by one . The 10th term exceed twice the fourth term by 3 find the first term