In order youngest to oldest, we have a,b,c,d where
a+b+c+d = 384
c-a = 14
b = a+3
d = 20+(c+a)/2
85,88,99,112
The four oldest people in Golden City have lived a total of 384 years put together. The difference in ages for the youngest and the second oldest is 14. The second youngest is 3 years older than the youngest. The oldest is 20 years older than the average of the second oldest and youngest find their ages and enter them from youngest to oldest.
1 answer
1 answer