Asked by Anonymous

The formula for rust is fe2o3 how many moles of (fe) are present in 30 g of rust ?
Answered by DrBob222
mm = molar mass
g Fe in 30 g Fe2O3 = 30 x (2*mm Fe/mm Fe2O3) = ?
mols Fe = g Fe/atomic mass Fe = ?
Answered by DrBob222
By the way, the formula for rust is much more complicated than Fe2O3. Also the formula appears to change with time and the amount of moisture in the reaction.
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