Asked by Anna
The formula for rust can be represented by Fe2O3. How many moles of Fe are present in 21.3g of the compound? Please help. I am SO confused on all of this!!
Answers
Answered by
DrBob222
What's the percent Fe in Fe2O3? That's (2*atomic mass Fe/molar mass Fe2O3)*100.
Then 21.3 g x fraction iron = g Fe.
Then 21.3 g x fraction iron = g Fe.
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