Question
The formula for rust is fe2o3 how many moles of (fe) are present in 30 g of rust ?
Answers
DrBob222
mm = molar mass
g Fe in 30 g Fe2O3 = 30 x (2*mm Fe/mm Fe2O3) = ?
mols Fe = g Fe/atomic mass Fe = ?
g Fe in 30 g Fe2O3 = 30 x (2*mm Fe/mm Fe2O3) = ?
mols Fe = g Fe/atomic mass Fe = ?
DrBob222
By the way, the formula for rust is much more complicated than Fe2O3. Also the formula appears to change with time and the amount of moisture in the reaction.