resultant N: 100N
reslultantW: 200W
resulatant: sqrt50000 in the direction arctan 2 N of W
acceleration=that force/4kg
The following four forces act on 4.00 kg object:
F1 = 300 N east
F2 = 700 N north
F3 = 500 N west
F4 = 600 N south
What is the acceleration of the object?
4 answers
F3-F1
500-300
200N west
F2-F4
700-600
100N north
100N north and 200N west
100^2+200^2=c^2
10000+40000=c^2
50000=c^2
√50000=c
100√5=c
223.6N
tanx=200/100
tanx=2
x=arctan(2)
x=63.4 degrees
223.6N, 63.4 degrees west of north.
f=ma
223.6/4=a
55.9m/s^2=a
55.9m/s^2 63.4 degrees west of north.
500-300
200N west
F2-F4
700-600
100N north
100N north and 200N west
100^2+200^2=c^2
10000+40000=c^2
50000=c^2
√50000=c
100√5=c
223.6N
tanx=200/100
tanx=2
x=arctan(2)
x=63.4 degrees
223.6N, 63.4 degrees west of north.
f=ma
223.6/4=a
55.9m/s^2=a
55.9m/s^2 63.4 degrees west of north.
1+1?
55.9 m/s2 in a direction 26.6∘ north of west.
2 answers