Convert 3.57 g KMnO4 to moles. mols = grams/molar mass.
Using the coefficients in the balanced equation, convert mols KMnO4 to mols Na2C2O4.
molarity Na2C2O4 = mols/L. YOu know mols from the above calculation, you know M, calculate volume.
Post your work if you get stuck.
The following equation describes the oxidation of an acidified solution of sodium oxalate (Na2C2O4) by potassium permanganate(KMnO4)
5C2O4 + 2MnO4 + 16H2SO4 --> 10CO2 + 2Mn + 16HSO4 + 8H20
What volume of 0.127M sodium oxalate in sulphuric acid will react with 3.57g of potassium permanganate?
4 answers
0.071L
M KMnO4 = 158.0339g/mol
1 mol
3.57g X -----------------
158.0339g KMnO4
5 mol C2O4-
= 0.02259009 mol KMnO4 X -------------
2 mol KMnO4
1 L
=0.056475225 mol C2O4-X ---------------
0.127 mol C2O4-
= 0.445 L
1 mol
3.57g X -----------------
158.0339g KMnO4
5 mol C2O4-
= 0.02259009 mol KMnO4 X -------------
2 mol KMnO4
1 L
=0.056475225 mol C2O4-X ---------------
0.127 mol C2O4-
= 0.445 L
Woops sorry about the spacing. I didn't realize it would come out like that. Hope you can read it.
1 answer