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Original Question
the following code is for python function to represent a recursive function to find the factorial of an ineger def factorial(x)...
The following code is for a Python function to represent a recursive function to find the factorial of an integer
def factorial(x):
if x == 1:
return 1
else:
return (x * factorial(x-1))
num = 3
print("The factorial of", num, "is", factorial(num))
Which code reflects the recursive case?
(1 point)
Responses
else:
return (x * factorial(x - 1))
else: return (x * factorial(x - 1))
if x == 1:
return 1
if x == 1: return 1
print("The factorial of", num, "is", factorial(num))
print("The factorial of", num, "is", factorial(num))
num = 3
num = 3
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def factorial(x):
if x == 1:
return 1
else:
return (x * factorial(x-1))
num = 3
print("The factorial of", num, "is", factorial(num))
Which code reflects the recursive case?
(1 point)
Responses
else:
return (x * factorial(x - 1))
else: return (x * factorial(x - 1))
if x == 1:
return 1
if x == 1: return 1
print("The factorial of", num, "is", factorial(num))
print("The factorial of", num, "is", factorial(num))
num = 3
num = 3
Skip to navigation
page 14 of 14
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The code that reflects the recursive case is:
```python
else:
return (x * factorial(x - 1))
```
This part of the function calls `factorial` within itself with the argument `x - 1`, which is what makes the function recursive.
```python
else:
return (x * factorial(x - 1))
```
This part of the function calls `factorial` within itself with the argument `x - 1`, which is what makes the function recursive.
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