Asked by ...
Consider the following code.
public void printNumbers(int x, int y) {
if (x < 5) {
System.out.println("x: " + x);
}
if (y > 5) { System.out.println("y: " + y);
}
int a = (int)(Math.random() * 10);
int b= (int)(Math.random() * 10);
if (x != y) printNumbers(a, b);
}
Which of the following conditions will cause recursion to stop with certainty?
x < 5
x < 5 or y > 5
x != y
x == y
public void printNumbers(int x, int y) {
if (x < 5) {
System.out.println("x: " + x);
}
if (y > 5) { System.out.println("y: " + y);
}
int a = (int)(Math.random() * 10);
int b= (int)(Math.random() * 10);
if (x != y) printNumbers(a, b);
}
Which of the following conditions will cause recursion to stop with certainty?
x < 5
x < 5 or y > 5
x != y
x == y
Answers
Answered by
oobleck
the only time recursion occurs is if x != y
so ...
so ...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.