The following chemical reaction takes place in aqueous solution:

Question

Cu(NO3)2(aq) +2 KOH(aq) —> Cu(OH)2(s)+2 KNO3(ag)
Write the net ionic equation for this reaction.

Answer 1

To write the net ionic equation for the given chemical reaction, we need to follow these steps:

1. **Write the balanced molecular equation with states of matter:**
\[
\text{Cu(NO}_3\text{)}_2\text{(aq)} + 2 \text{KOH(aq)} \rightarrow \text{Cu(OH)}_2\text{(s)} + 2 \text{KNO}_3\text{(aq)}
\]

2. **Separate the soluble compounds into their respective ions (complete ionic equation):**
\[
\text{Cu}^{2+}\text{(aq)} + 2 \text{NO}_3^{-}\text{(aq)} + 2 \text{K}^{+}\text{(aq)} + 2 \text{OH}^{-}\text{(aq)} \rightarrow \text{Cu(OH)}_2\text{(s)} + 2 \text{K}^{+}\text{(aq)} + 2 \text{NO}_3^{-}\text{(aq)}
\]

3. **Identify and cancel out the spectator ions:**
Spectator ions are ions that appear on both sides of the equation and do not participate in the actual chemical change. In this case, the \(\text{K}^+\) and \(\text{NO}_3^-\) ions are the spectator ions.
\[
\text{Cu}^{2+}\text{(aq)} + 2 \text{OH}^{-}\text{(aq)} \rightarrow \text{Cu(OH)}_2\text{(s)}
\]

4. **Write the net ionic equation:**
\[
\text{Cu}^{2+}\text{(aq)} + 2 \text{OH}^{-}\text{(aq)} \rightarrow \text{Cu(OH)}_2\text{(s)}
\]

This is the net ionic equation for the reaction, showing only the species that actually undergo a chemical change.