To write the net ionic equation for the reaction AgF(aq) + KBr(aq) -> AgBr(s) + KF(aq), follow these steps:
1. **Write the balanced molecular equation.**
\[ \text{AgF}(aq) + \text{KBr}(aq) \rightarrow \text{AgBr}(s) + \text{KF}(aq) \]
2. **Dissociate all strong electrolytes (soluble ionic compounds) into their ions.**
\[ \text{Ag}^+ (aq) + \text{F}^- (aq) + \text{K}^+ (aq) + \text{Br}^- (aq) \rightarrow \text{AgBr}(s) + \text{K}^+ (aq) + \text{F}^- (aq) \]
3. **Identify and remove the spectator ions.**
Spectator ions are ions that appear unchanged on both sides of the equation. In this reaction, the spectator ions are \(\text{K}^+\) and \(\text{F}^-\).
4. **Write the net ionic equation by eliminating the spectator ions from the complete ionic equation.**
\[ \text{Ag}^+ (aq) + \text{Br}^- (aq) \rightarrow \text{AgBr}(s) \]
So, the net ionic equation for the reaction is:
\[ \text{Ag}^+ (aq) + \text{Br}^- (aq) \rightarrow \text{AgBr}(s) \]
The following chemical reaction takes place in aqueous solution:
AgF(aq)+KBr(aq)->AgBr(s)+KF(aq)
Write the net ionic equation for this reaction
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