The floor of a rectangle hall is of length 9m and width 4m .How many tiles of 20ck by 30cm can be used to cover the floor completely.

Answer 1

I don't know .
Pls help me with it

Answer 2

dont know

Answer 3

It sort of depends in which pattern you lay the tiles
Since the length of 900 cm and width of 400 cm for the room are multiples of both 20 cm and 30 cm, using the same orientation of the tiles, you will need
(900)(400) / (20)(30) tiles = 600 tiles

or
the short end of the tile along the 400 cm floor would be 400/20 and the long
end of the room would be 900/30 , so 20(30) = 600
or
the long end of the tile along the 400 cm floor would be 400/30 = 13 1/3 tiles
the short end of the tile along the 900 cm floor would be 900/20 = 45 tiles
assuming we will not be able to cut tiles without loss we will need
13(45) + 45 or 630 for this case

we could also lay them as 20 cm, 30 cm, 20 cm, 30 cm ... along both
the length and the width.
Since the pattern would then be 50 cm in length, and 50 divides
evenly into both 900 and 400, that would also need 600 tiles

but suppose you try to be fancy, and lay 2 tiles along their width, followed by a tile along its length. So that pattern would be 20+20+30 or 70 cm long
Along the length of the room of 900 cm you would be able to do this
900/70 or 12.8.. times, that is, you will need a partial tile at the end of
both the length and the width of the room.
This is just one example of a "pattern".

My guess is that they didn't take that into consideration, and let's go
with 600 tiles.