The floor of a lorry is 2.0m high. A plank 5m long is used as an inclined plane to raise some load up the lorry. If the efficiency of this machine is 50% what is the minimum effort (applied parallel to the plane) required to raise 200N load up the plane?

Answer 1

work done to raise 200 N up 2 meters = 400 Joules
work needed at 50% efficiency = 800 Joules
distance pushed = 5 meters
so 5 F = 800
F = (800/5) Newtons

Answer 2

Thanks 😊

Answer 3

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Answer 4

5/2=2.5 efficiency=ma/vr×100% 50%=ma/2.5×100ma=50×2.5divided by 100=1.25 therefore 1.25=load/effort=200/effort effort=200/1.25=160Nanswer

Answer 5

the flour of a long is 2.0 high. A plank 5m is used as an inclined to plane to raise some load up the lorry it the efficiency of this machine is 50% what is the maximum effort applied parallel to plane required 10 raised 200n load up the plane

Answer 6

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