The first step of the synthesis is described by the reaction below. When 1.750 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4, the theoretical yield of FeC2O42H2O is____

Question

grams.

Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)---->
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)

Answer 1

you have grams of product and you have moles from the equation so you can find the mass of product theoretically formed.
usually you would find the limiting reagent but here it's a 1:1 ratio so it doesn't matter.

1.750g Fe(NH4)2(SO4)2 6H2O x(1 molFe(NH4)2(SO4)2 6H2O/__g)(1mol FeC2O42H2O/1mol Fe(NH4)2(SO4)2 6H2O )= _________moles of product formed from Fe(NH4)2(SO4)2 6H2O

13 mL(1L/1000ml)(1mol H2C2O4/L)( 1mol FeC2O42H2O/1mol H2C2O4)= _______moles of product formed from H2C2O4

_____________

The reactant that produces the least moles of product is the limiting reagent.
Take that number of moles of product formed and use it to form the theoretical yield of product.

(____moles of FeC2O42H2O)(____g FeC2O42H2O/ 1 mol)= _____________g FeC2O42H2O produced.

If you need clarification on anything just ask.