The first side of a triangle is 8 meters longer than twice the second side. The third side is 3 times the second side. The perimeter is 128 meters. Find the lengths of the three sides.

Answer 1

Let x = second side

First side = 2x +8

Third side = 3x

x + (2x + 8) + 3x = 128

Solve for x, then the other sides.

I hope this helps.

Answer 2

Let b = 2nd side
2b + 8 = 1st side
3b = 3rd side

x + (2x + 8) + 3x = 128
6b + 8 = 128
*REMOVE 8 FROM BOTH SIDES*
6b = 120
*DIVIDE*
b = 20