Questions and answers by

D34PF4YK3

Answers (1)

Let b = 2nd side 2b + 8 = 1st side 3b = 3rd side x + (2x + 8) + 3x = 128 6b + 8 = 128 *REMOVE 8 FROM BOTH SIDES* 6b = 120 *DIVIDE* b = 20

Ask a New Question