The figure shows a girl and a boy each exerting a force to move a

Question

crate horizontally a distance of 13 m at a constant speed. The girl’s
applied force is 75 N [22° below the horizontal]. The tension in the
rope pulled by the boy is 75 N [32° above the horizontal].

Answer 1

horizontal force exerted = 75 cos 22 +75 cos 32

vertical force exerted = 75 (sin 32 -sin22)

normal force on ground = m g - 75(sin32-sin22)

friction force = mu (normal force)

acceleration = 0
so
friction force = horizontal force exerted

work done = 13 * friction force

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