The fictitious compound, pandemonium carbonate Pn(CO3)2 hase a Ksp=3.091×10−9 M3 in water at room temperature. Calculate the solubility of Pn(CO3)2 in an aqueous solution of 1.11 M pandemonium sulfate Pn(SO4)2 (aq). Express your answer in units of molarity.
1 answer
2.639 x 10^-5
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