The fictitious compound, pandemonium carbonate Pn(CO3)2 hase a Ksp=3.091x10^-9M3 in water at room temperature. Calculate the solubility of Pn(CO3)2 in an aqueous solution of 1.11 M pandemonium sulfate Pn(SO4)2 (aq) . Express your answer in units of molarity.

Answer 1

please, i need the answer too!

Answer 2

2.63e-5

Answer 3

0.917e-3

Answer 4

I had 2.63e-5 as the right answer

Answer 5

qwerty and paul are right. Thank you both.