Asked by John
The expression dy/dx = x(cube root^3 y) gives the slope at any point on the graph of the function f(x) where f(2) = 8.
- equation of the tangent line f(x) at point (2,8) = (y-8)=4(x-2)
- expression for f(x) in terms of x = f(x)=[x^2/3+8/3]^3/2
-domain all real numbers.
-minimum [8/3]^3/2
Using the axes provided, sketch a slope field for the given differential equation at the nine points indicated. gyazo.com/d1944f7a206262301c82db884f090464
- equation of the tangent line f(x) at point (2,8) = (y-8)=4(x-2)
- expression for f(x) in terms of x = f(x)=[x^2/3+8/3]^3/2
-domain all real numbers.
-minimum [8/3]^3/2
Using the axes provided, sketch a slope field for the given differential equation at the nine points indicated. gyazo.com/d1944f7a206262301c82db884f090464
Answers
Answered by
oobleck
You have all the answers, and I assume you can plot the points.
So, what's your question? Just calculate the slope at each point, and draw little line segments at each point. You should get a slope field, and you want to pick the one that makes the curve go through (2,8)
This link should help.
https://www.desmos.com/calculator/wlrpptwfgl
So, what's your question? Just calculate the slope at each point, and draw little line segments at each point. You should get a slope field, and you want to pick the one that makes the curve go through (2,8)
This link should help.
https://www.desmos.com/calculator/wlrpptwfgl
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.