You have all the answers, and I assume you can plot the points.
So, what's your question? Just calculate the slope at each point, and draw little line segments at each point. You should get a slope field, and you want to pick the one that makes the curve go through (2,8)
This link should help.
https://www.desmos.com/calculator/wlrpptwfgl
The expression dy/dx = x(cube root^3 y) gives the slope at any point on the graph of the function f(x) where f(2) = 8.
- equation of the tangent line f(x) at point (2,8) = (y-8)=4(x-2)
- expression for f(x) in terms of x = f(x)=[x^2/3+8/3]^3/2
-domain all real numbers.
-minimum [8/3]^3/2
Using the axes provided, sketch a slope field for the given differential equation at the nine points indicated. gyazo.com/d1944f7a206262301c82db884f090464
1 answer
1 answer