Asked by Nate Williams
Jan built a cube from unit cubes (each 1 by 1 by 1 unit). Ken took this cube apart,and used the unit cubes to build a rectangular solid that was the same height asJan's cube but 2 units greater in width and 2 units less in length. Ken had 24 unit cubes left over. How many unit cubes did Ken use to build his figure?
Answers
Answered by
Reiny
solve
x^3 - x(x+2)(x-2) = 24
x^3 - x(x^2-4) = 24
x^3 - x^3 + 4x = 24
4x=24
x=8
So Jan used 8^3 or 515 cubes
Ken used 24 less or 488 cubes
check:
original:
8^3 = 512
Ken's cube = 8 x 6 x 10 = 480
512-480=24
x^3 - x(x+2)(x-2) = 24
x^3 - x(x^2-4) = 24
x^3 - x^3 + 4x = 24
4x=24
x=8
So Jan used 8^3 or 515 cubes
Ken used 24 less or 488 cubes
check:
original:
8^3 = 512
Ken's cube = 8 x 6 x 10 = 480
512-480=24
Answered by
Nate Williams
Thanks much.
Answered by
JMY
The answer is X=6, not X=8. Ken's cube was 6 x 4 x 8 = 192, Jan's was 6 x 6 x 6 = 216. 216 - 192 = 24.
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