Asked by Miley
the equlibrium equation is (I2)^2(CO2)^5/(CO)^5.
If the (CO) starts at 1.0 M and decreases to 0.25 M at equilibrium, give the value of Keq.
How would i do that??
If the (CO) starts at 1.0 M and decreases to 0.25 M at equilibrium, give the value of Keq.
How would i do that??
Answers
Answered by
DrBob222
Have you omitted something? Where does the I2 come in? And how does the CO get to CO2? The equation must be somthing like this.
5CO + ?? ==> 5CO2 + I2
5CO + ?? ==> 5CO2 + I2
Answered by
Brittney
I2O5=??
Answered by
DrBob222F
If you have a question to post, I suggest you go to the top of the page, click on post a new question and post it. Posting on another question piggy-back style often leads to it being overlooked. What about I2O5. Do you want the name? Its density. Its color? what? I would name it diiodidopentoxide or diiodine pentoxide.
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