Asked by Kristen
The equlibrium constant K, for the reaction, H2 + CO2 <-> H20 + CO, is 4.2 at 1650 degrees C. Initially, 0.80 mol H2 and 0.80 mol CO2 are injected into a 5.0L flask. Calculate the concentration of each species at equilibrium.
Answers
Answered by
DrBob222
..........H2 + CO2 ==> H2O + CO
initial.0.80...0.80.....0.....0
change....-x.....-x......x.....x
equil..0.80-x..0.80-x....x.....x
Kc = 4.2 = (H2O)(CO)/(H2)(CO2)
Solve for x = mols, then x/5.0L = concn.
initial.0.80...0.80.....0.....0
change....-x.....-x......x.....x
equil..0.80-x..0.80-x....x.....x
Kc = 4.2 = (H2O)(CO)/(H2)(CO2)
Solve for x = mols, then x/5.0L = concn.
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