That is a parabola.
If you know calculus, set dP/di = 0
I will continue assuming you do not know calculus and finding the vertex of the parabola by completing the square
- 8 i^2 + 240 i = P
i^2 - 30 i = - P/8
i^2 - 30 i +(30/2)^2 = -P/8 + 225
(i-15)^2 = -P/8 + 225
vertex at i = 15 and P at 225*8 = 1800
The equation P=240I-8I^2 represents the power, P, (in watts) of a 240 volt circuit with a resistance of 8 ohms when a current of I amperes is passing through the circuit.
Find the maximum power (in watts)that can be delivered in this circuit.
I have trouble to find the maximum power,please help! THANKS A LOT!
3 answers
From this part on, I don't really get it:
i^2 - 30 i +(30/2)^2 = -P/8 + 225
(i-15)^2 = -P/8 + 225
vertex at i = 15 and P at 225*8 = 1800
Can you please explain???
i^2 - 30 i +(30/2)^2 = -P/8 + 225
(i-15)^2 = -P/8 + 225
vertex at i = 15 and P at 225*8 = 1800
Can you please explain???
I solved that quadratic equation by "completing the square".
when you have the equation in the form:
1 x^2 + b x = -c
take half of b and square it
(b/2)^2 in this case (30/2)^2 = 15^2 = 225
add that to both sides
1 x^2 + b x + (b/2)^2 = - c + (b/2)^2
the left side factors
(x + b/2)(x + b/2) = -c + (b/2)^2
in our case b/2 = 15 so (b/2)^2 = 225
or
(x+b/2)^2 = -c + (b/2)^2
in our case
(x-15)^2 = -P/8 + 15^2
take sqrt of both sides remembering that - the square root is also a solution.
x+b/2 = +/- sqrt( b^2/4 - 4c/4)
x = (- b/2 +/- (1/2)sqrt ( b^2 - 4 c)
which you will recognize as the quadratic equation with a = 1
We fixed a as one by dividing by a right at the start.
The main thing is that -b/2a or in our case -b/2 is the axis of symmetry of the parabola. If the parabola faces up (holds water), the minimum is there. If the parabola faces down ( sheds water - our case), the maximum is there.
when you have the equation in the form:
1 x^2 + b x = -c
take half of b and square it
(b/2)^2 in this case (30/2)^2 = 15^2 = 225
add that to both sides
1 x^2 + b x + (b/2)^2 = - c + (b/2)^2
the left side factors
(x + b/2)(x + b/2) = -c + (b/2)^2
in our case b/2 = 15 so (b/2)^2 = 225
or
(x+b/2)^2 = -c + (b/2)^2
in our case
(x-15)^2 = -P/8 + 15^2
take sqrt of both sides remembering that - the square root is also a solution.
x+b/2 = +/- sqrt( b^2/4 - 4c/4)
x = (- b/2 +/- (1/2)sqrt ( b^2 - 4 c)
which you will recognize as the quadratic equation with a = 1
We fixed a as one by dividing by a right at the start.
The main thing is that -b/2a or in our case -b/2 is the axis of symmetry of the parabola. If the parabola faces up (holds water), the minimum is there. If the parabola faces down ( sheds water - our case), the maximum is there.