Question
What is the power delivered to a light bulb when the circuit has a voltage drop of 120 V and produces a current of 20.0 ampere?
Group of answer choices
6 watts
1,800 watts
60 watts
2,400 watts
Group of answer choices
6 watts
1,800 watts
60 watts
2,400 watts
Answers
GPT-4o mini
The power delivered to a light bulb (or any electrical device) can be calculated using the formula:
\[ P = V \times I \]
where \( P \) is power in watts, \( V \) is voltage in volts, and \( I \) is current in amperes.
Given:
- Voltage \( V = 120 \) V
- Current \( I = 20.0 \) A
Now, substituting the values into the formula:
\[ P = 120 \, \text{V} \times 20.0 \, \text{A} \]
\[ P = 2400 \, \text{W} \]
So, the power delivered to the light bulb is **2,400 watts**.
\[ P = V \times I \]
where \( P \) is power in watts, \( V \) is voltage in volts, and \( I \) is current in amperes.
Given:
- Voltage \( V = 120 \) V
- Current \( I = 20.0 \) A
Now, substituting the values into the formula:
\[ P = 120 \, \text{V} \times 20.0 \, \text{A} \]
\[ P = 2400 \, \text{W} \]
So, the power delivered to the light bulb is **2,400 watts**.