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the equation of the line for a graph of voltage versus log[Cu2+] was y= - 0.0179x - 0.0015. The voltage of a solution with an u...Asked by Max
The equation of the line for a graph of voltage versus log[Cu2+] was y= - 0.0179x - 0.0015. The voltage of a solution with an unknown [Cu2+] was measured against the same reference cell, under the same conditions; the voltage was found to be 0.012 V. Determine the [ Cu2+] of the unknown solution.
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Anonymous
y = 0.012 V = - 0.0179x - 0.0015
x = log[Cu2+]
10^x = [Cu2+]
x = log[Cu2+]
10^x = [Cu2+]
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