y-y1 =m(x-x1)
y=5=-3x-*(x-1)
y-5=-3x-3
y-5+3=-2+1=
y=-3
I don't know if this is correct
the equation of a line parallel to the given line but passing through the given point. I can't figure out.
y=-3x-6;(-1, 5)
3 answers
The given line has slope -3
So, the parallel line also has that slope. Now you have a point and a line, so the equation is
y-5 = -3(x+1)
y = -3x+2
Your first line was okay, but then you started dropping x's along the way.
x1 = -1, not 1.
So, the parallel line also has that slope. Now you have a point and a line, so the equation is
y-5 = -3(x+1)
y = -3x+2
Your first line was okay, but then you started dropping x's along the way.
x1 = -1, not 1.
Thank You Steve I will note that thanks again !
1 answer