Asked by vhena
in triangle abc, a line parallel to AC intersects at AB at D and BC at E . If db is 6, ad is 2 and bc is 24, find de if ab and bc include a 60 degree angle
Answers
Answered by
Reiny
by the cosine law:
AC^2 = 8^2 + 24^2 - 2(8)(24)cos60°
= 448
AC = √448 = 8√7
now by similar triangles:
DE/8√7 = 6/8
DE = 48√7/8 = 6√7
AC^2 = 8^2 + 24^2 - 2(8)(24)cos60°
= 448
AC = √448 = 8√7
now by similar triangles:
DE/8√7 = 6/8
DE = 48√7/8 = 6√7
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