If you canceled out the x+3 terms, that leaves the x-3 terms, so your quotient is
1/(x-3)^2
But your answer is indeed 1/36
The equation is x^2+6x+9/x^4-81
Limit is x➡️-3
I factored it out and I got 1/36 would that be right
The numerator would factor out to be (x+3)(x+3) then the denominator would be (x+3)(x-3)(x+3)(x-3) this would cancel out the (x+3) which would leave 1/x^2+6x+9 the plugging in -3 I got 1/36 I don't know if that is right
2 answers
X^2 +6x+9/x^4-81
I put the answer as 1/36 it's not the answer??
It told me to use the identity x^4-a^4=(x+a)(x-a)(x^2+a^2) I used it u still get the same answer....
I put the answer as 1/36 it's not the answer??
It told me to use the identity x^4-a^4=(x+a)(x-a)(x^2+a^2) I used it u still get the same answer....
0 answers