1. I would choose B.
2. c^2 - 10c = c(c-10) = 0
Now what do you think?
4. z^2 - 12z + 36 = (z-6)(z-6) = 0
Now what do you think?
3. Since it seems like you are just guessing, I did not bother to answer.
1)What method(s) would you choose to solve the equation:
x2 + 2x - 6 = 0
A. Square roots; there is no x-term.
B. Quadratic formula, graphing; the equation cannot be factored easily since the numbers are large.
C. Factoring; the equation is easily factored.
D. Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored. <<<------
2)What are the solutions of the equation?
c^2 - 10c = 0
A. 1, – squareroot10 <<<----
B. 0, –10
C. 0, sqrt10
D. 0, 10
3)Use the discriminant to determine the number of real-number solutions for the equation:
8x2 + 8x + 2 = 0
A. one solution <<<---
B. two solutions
C. no solutions
D. infinitely many solutions
4)What are the solutions of the equation: z2 - 12z + 36 = 0?
A. -6, 6 <<----
B. 6, 6
C. 6, -6
D. -6, -6
am i right? if not, please help me out. :D
thank u!
1 answer
1 answer