The equation 10(x-1)(x-2)(x-3) = 1 has three real solutions a<b<c where a = , b = , and c = . Enter your answers with at least six correct digits beyond the decimal point. Hint: Ask what the solutions are if the right hand side is 0 instead of 1, and use Newton's Method.

Answer 1

Just as a check on your final values, I get

1.0544
1.8990
3.0467

Your final 6 digits should extend these values

Answer 2

the first two are wrong

Answer 3

10(1.0544-1)(1.0544-2)(1.0544-3) = 1.0008

Looks pretty close to me.