2C + 3H2 + 1/2 O2 --> C2H5OH dH = -238.7 kJ/mol.
Doesn't - tell you that heat is released. That makes the answer D.
The enthalpy of formation of C2H5OH is -238.7 kJ/mol. What information does this reveal about the bonds in the molecule?
A. Bond formation in C2H5OH from its elements only occurs in cold temperatures.
B. Bond formation in C2H5OH from its elements does not occur.
C. Bond formation in C2H5OH from its elements absorbs energy.
D. Bond formation in C2H5OH from its elements releases energy.
1 answer