The enthalpy change for the following reaction is -483.6 kJ:
2H2(g) + O2(g) = 2H2O(g)
Therefore, the enthalpy change for the following reaction is _______ kJ: 4H2(g) + 2O2(g) = 4H2O(g)
1 answer
You have doubled the reaction; wouldn't the new enthalpy change be just twice as much.