kC < kA < kB
Since heat is conducted from left to right, the temperature at the interface between the first and second cylinder will be higher than at the interface between the second and third cylinder. This means that the material with the highest thermal conductivity is at the interface with the highest temperature, which is the interface between the first and second cylinder. Thus, the order of thermal conductivities from lowest to highest is kC < kB < kA.
The drawing shows three cylinders that have the same length and cross-sectional areas, but each is made of different material. The cylinders are arranged in series, so that heat is conducted from the left toward the right. The temperatures at the interfaces between the materials are indicated. Rank the thermal conductivities of the three materials, which are labeled A, B, and C, from the lowest to the highest value.
kB < kC < kA
kA < kC < kB
kC < kA < kB
kA < kB < kC
kB < kC < kA
1 answer
1 answer