got it,
a) the stress is
F/A= mg/A = 156(9.8)/7.44*10^-4= 2.05*10^6 N/m^2
B) F=S(delta y/ Lo)A,, solve for delta y
delta y= (F/A)*(Lo/S)
the value of F/A was found in part a, so substitute the answer in the second equation.
2.05*10^6(0.117/8.1*10^10)=2.96*10^-6m
The drawing shows a 156-kg crate hanging from the end of a steel bar (S = 8.1 x 1010 N/m2). The length of the bar is 0.117 m, and its cross-sectional area is 7.44 x 10-4 m2. Neglect the weight of the bar itself and determine (a) the shear stress on the bar and (b) the vertical deflection Y of the right end of the bar.
I know that I have to use the equation to solve, but don't know how to start, If you could help explain the steps, I'll appreciate it.
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