The doubling period of a baterial population is 10 minutes. At time t=80 minutes, the baterial population was 50000

Question

1What was the initial population at time t=0
2Find the size of the baterial population after 4 hours

Answer 1

Note that 80 minutes is 8 doubling periods, for a growth of 2^8 = 256 times.

So, initially there were 50000/256 bacteria.

I think you can take it from there, no?