Question
The doubling period of a baterial population is 20 minutes. At time t=100 minutes, the baterial population was 80000. What was the initial population at time t=0?
Find the size of the baterial population after 4 hours.
Answers
drwls
Note the correct spelling of your subject.
Let the initial population be No and the doubling time be T (= 20 minutes)
No*2^(t/T) = No*2^5 = 80,000
32 No = 80,000
No = 2500
After 4 hours (t = 240 minutes),
N = No*2^(240/20) = 2500*2^12
= 10.24*10^6
Let the initial population be No and the doubling time be T (= 20 minutes)
No*2^(t/T) = No*2^5 = 80,000
32 No = 80,000
No = 2500
After 4 hours (t = 240 minutes),
N = No*2^(240/20) = 2500*2^12
= 10.24*10^6