just solve
t^2-2t = 48
t^2-2t-48 = 0
(t-8)(t+6) = 0
I expect you can take it from there, no?
The distance traveled by an object moving in a straight line is given by s = t2 − 2t,
where s is in feet and t is the time in seconds the object has been in motion. How long
(to the nearest tenth) will it take the object to move 48 feet?
1 answer
1 answer