The distance between the second and sixth crests in a wave is 75cm and one crest travels a distance of 25 cm in 3.0s . Find the frequency of the wave

Answer 1

λ=0.3 m.
v=s/t =0.25/3 m/s.
λ =v/f,
f=v/λ =0.25/3•0.3 =0.28 Hz

Answer 2

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Answer 3

The distance across four waves is 75 cm, therefore,
λ = 18.75 cm
Δd = 25 cm
Δt = 3.0 s
f =?
v = Δd
Δt
= 25 cm
3.0 s
= 8.333 cm/s
v = fλ
f = v
λ
= 8.333 cm/s
18.75 cm
= 0.4444 s−1
= 0.4444 Hz