differentiating ... ds/dt = 2 t - 5
plug in 8 for t
The displacement (in feet) of a particle moving in a straight line is given by
s = 1/2t^2 − 5t + 15, where t is measured in seconds. Find the instantaneous velocity (in ft/s) when t = 8.
4 answers
ds/dt should have been
t - 5
t - 5
yup ... go with the update ... blizzard blindness ...
s = 1/2t^2 - 5t + 15
ds/dt = t - 5
ds/dt = 8 - 5
ds/dt = 3
Therefore, the instantaneous velocity of the particle after 8 seconds is 3 ft/s.
ds/dt = t - 5
ds/dt = 8 - 5
ds/dt = 3
Therefore, the instantaneous velocity of the particle after 8 seconds is 3 ft/s.
1 answer