when t = 1, s = 3sinฯ + 3 cosฯ = 3(0) + 3(-1) = -3
when t = 1.01, s = 3sin(1.01ฯ) + 3cos(1.01ฯ) = -3.0927
when t = 1.001, s = 3sin(1.001ฯ) + 3cos(1.001ฯ) = -3.00949958
avg velocity between t = 1 and t = 1.01 = (-3.0927 + 3)/(1.01-1)
= appr -9.28
avg velocity between t = 1 and t = 1.001 = (-3.0094... + 3)/.001
= appr -9.41
btw, just in case you may be interested -3ฯ = -9.425
mmmhhh?
The displacement (in centimeters) of a particle s moving back and forth along a straight line is given by the equation s = 3 sin(๐t) + 3 cos(๐t), where t is measured in seconds. (Round your answers to two decimal places.)
(a)Find the average velocity during each time period.
(i)[1, 1.01]cm/s
(ii)[1, 1.001]cm/s
(b)Estimate the instantaneous velocity of the particle when t = 1.
1 answer