The different between the 11th term of an AP is 49 and if the 11th term is 74/25 times the 4th term determine ,the common difference ,the first term of the sequence and the 6th term of the sequence

Answer 1

"The difference between the 11th term of an AP is 49"
makes no sense.
difference between T11 and what?

but the second criterion is

a+10d = 74/25 (a+3d)

Answer 2

The difference between the 11th term and 4th of an A.P is 49 and if the 11th term is 74 times the fourth term determine A the common difference B first term

Answer 3

T11-T4=49
a+10d-(a+3d)=49
a+10d-a-3d=49
10d-3d=49
7d=49
d=7

T11=74/25×T4
a+10d = 74/25×a+3d
a+10d=74a+222d
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25

25(a+10d)=74a+222d
25a+250d=74a+222d
25a-74a=222d-250d
-49a=-196
a=4

Where a is first num
d is common difference
6th term = a + 5d
Then substitute

Answer 4

How did u gett 222d

Answer 5

74 times 3

Answer 6

Favour