The difference of two numbers is 47. The larger number is three less than six times the smaller number. Find the numbers.

2 answers

L = S + 47

L = 6S - 3

Substitute S+47 for L in the second equation and solve for L. Insert that value into the first equation to solve for S. Check by putting both values into the second equation.
S+47=6S-3
+3 +3
S+50=6S
-S -S
50= 5S
10=S
L=S+47
L=(10)+47
L=57